document.write( "Question 87473: Solve. \r
\n" ); document.write( "\n" ); document.write( "The square root of x-1 = x-3\r
\n" ); document.write( "\n" ); document.write( "I got as far as x=x^2-6x+10 but don't know what to do next. Please explain.
\n" ); document.write( "Thank you.
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Algebra.Com's Answer #63395 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
\"sqrt%28x-1%29+=+x-3\"
\n" ); document.write( "\"x-1+=+%28x-3%29%5E2\"
\n" ); document.write( "\"x-1=+x%5E2+-6x%2B9\"\r
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\n" ); document.write( "\n" ); document.write( "Now, since this is a quadratic equation, you must set it equal to zero by subtracting x and adding +1 to each side:
\n" ); document.write( "\"0=x%5E2+-7x+%2B10\"\r
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\n" ); document.write( "\n" ); document.write( "This factors! By the way in radical equations, they ALWAYS factor!!\r
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\n" ); document.write( "\n" ); document.write( "\"0=%28x-5%29%28x-2%29+\"
\n" ); document.write( "x=5 or x=2\r
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\n" ); document.write( "\n" ); document.write( "You MUST check the answers, since you squared both sides of the equation!!\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28x-1%29+=+x-3\"\r
\n" ); document.write( "\n" ); document.write( "Check: x=5
\n" ); document.write( "\"sqrt%285-1%29+=+5-3\"
\n" ); document.write( "\"sqrt%284%29=+2\" It checks!!\r
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\n" ); document.write( "\n" ); document.write( "Check: x=2
\n" ); document.write( "\"sqrt%282-1%29+=+2-3\"
\n" ); document.write( "\"sqrt%281%29=+-1\" It does NOT check!!
\n" ); document.write( "You must reject the value of x=2.\r
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\n" ); document.write( "\n" ); document.write( "Final answer is x=5 only!\r
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\n" ); document.write( "\n" ); document.write( "R^2 Retired from SCC\r
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