document.write( "Question 1017682: h. The length of a rectangle is 20 meters longer than the width. The perimeter must be
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document.write( "between 80 and 100 meters. What are the possible values for the width of the rectangle? \n" );
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Algebra.Com's Answer #633932 by addingup(3677) You can put this solution on YOUR website! L = W+20 \n" ); document.write( "2(W+20)+2W = 80 \n" ); document.write( "2W+40+2W = 80 \n" ); document.write( "4W = 40 \n" ); document.write( "W = 10 \n" ); document.write( "and \n" ); document.write( "2(W+20)+2W = 100 \n" ); document.write( "4W+40 = 100 \n" ); document.write( "4W = 60 \n" ); document.write( "W = 15 \n" ); document.write( "so the possible values fall between a width of 10 and a width of 15 \n" ); document.write( "J \n" ); document.write( " |