document.write( "Question 1017264: the area of a rectangle wall of a barn is 168 squate feet. its lenght is 10 feet longer than twice its width. find the lenght and width of the wall of the barn. \n" ); document.write( "
Algebra.Com's Answer #633843 by Cromlix(4381)\"\" \"About 
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Hi there,
\n" ); document.write( "Make width = x
\n" ); document.write( "Length = 2x + 10
\n" ); document.write( "Area = Width * length (* = times)
\n" ); document.write( "168 = x(2x + 10)
\n" ); document.write( "168 = 2x^2 + 10x
\n" ); document.write( "2x^2 + 10x - 168 = 0
\n" ); document.write( "2(x^2 + 5x - 84) = 0
\n" ); document.write( "2(x + 12)(x - 7) = 0
\n" ); document.write( "x + 12 = 0
\n" ); document.write( "x = -12 (Disregard as -ve)
\n" ); document.write( "x - 7 = 0
\n" ); document.write( "x = 7
\n" ); document.write( "Width = 7 ft
\n" ); document.write( "Length = 24 ft
\n" ); document.write( "Hope this helps :-)
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