document.write( "Question 1017264: the area of a rectangle wall of a barn is 168 squate feet. its lenght is 10 feet longer than twice its width. find the lenght and width of the wall of the barn. \n" ); document.write( "
Algebra.Com's Answer #633843 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "Make width = x \n" ); document.write( "Length = 2x + 10 \n" ); document.write( "Area = Width * length (* = times) \n" ); document.write( "168 = x(2x + 10) \n" ); document.write( "168 = 2x^2 + 10x \n" ); document.write( "2x^2 + 10x - 168 = 0 \n" ); document.write( "2(x^2 + 5x - 84) = 0 \n" ); document.write( "2(x + 12)(x - 7) = 0 \n" ); document.write( "x + 12 = 0 \n" ); document.write( "x = -12 (Disregard as -ve) \n" ); document.write( "x - 7 = 0 \n" ); document.write( "x = 7 \n" ); document.write( "Width = 7 ft \n" ); document.write( "Length = 24 ft \n" ); document.write( "Hope this helps :-) \n" ); document.write( " |