document.write( "Question 1017574: A teacher's table is to be constructed such that the width is 3/5 of the length. If the perimeter is 72 inches find the area of the rectangle\r
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Algebra.Com's Answer #633841 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
Hi there,
\n" ); document.write( "Make length = x
\n" ); document.write( "Width = 3/5x
\n" ); document.write( "Perimeter = 2(length) + 2(width)
\n" ); document.write( "72 = 2(x) + 2(3/5x)
\n" ); document.write( "72 = 2x + 6/5x
\n" ); document.write( "72 = 16/5x
\n" ); document.write( "72*5/16 = x (* = times)
\n" ); document.write( "x = 22.5 inches
\n" ); document.write( "Length = 22.5 inches
\n" ); document.write( "Width = 13.5 inches
\n" ); document.write( "Area = length * width
\n" ); document.write( "Area = 22.5 * 13.5 = 303.75 ins^2
\n" ); document.write( "Hope this helps :-)
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