document.write( "Question 1017574: A teacher's table is to be constructed such that the width is 3/5 of the length. If the perimeter is 72 inches find the area of the rectangle\r
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #633841 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "Make length = x \n" ); document.write( "Width = 3/5x \n" ); document.write( "Perimeter = 2(length) + 2(width) \n" ); document.write( "72 = 2(x) + 2(3/5x) \n" ); document.write( "72 = 2x + 6/5x \n" ); document.write( "72 = 16/5x \n" ); document.write( "72*5/16 = x (* = times) \n" ); document.write( "x = 22.5 inches \n" ); document.write( "Length = 22.5 inches \n" ); document.write( "Width = 13.5 inches \n" ); document.write( "Area = length * width \n" ); document.write( "Area = 22.5 * 13.5 = 303.75 ins^2 \n" ); document.write( "Hope this helps :-) \n" ); document.write( " |