document.write( "Question 1017564: a rectangular field is 6 times as long as it is wide. if the length is decreased by 4m and the width is increased by 2m, the perimeter will be 52m. find the dimensions of the original field \n" ); document.write( "
Algebra.Com's Answer #633824 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "a rectangular field is 6 times as long as it is wide \n" ); document.write( "Make the width = x \n" ); document.write( "Length = 6x \n" ); document.write( "if the length is decreased by 4m and the width is \n" ); document.write( "increased by 2m, \n" ); document.write( "Length = 6x - 4 Width = x + 2 \n" ); document.write( "the perimeter will be 52m. \n" ); document.write( "Perimeter = 2(Width) + 2(Length) \n" ); document.write( "52 = 2(x + 2) + 2(6x - 4) \n" ); document.write( "52 = 2x + 4 + 12x - 8 \n" ); document.write( "Collect like terms \n" ); document.write( "2x + 12x = 52 - 4 + 8 \n" ); document.write( "14x = 56 \n" ); document.write( "x = 4 \n" ); document.write( "Dimensions of original field: \n" ); document.write( "Width = 4m \n" ); document.write( "Length = 24m \n" ); document.write( "Hope this helps :-) \n" ); document.write( " |