document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1017527>Question 1017527</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Using benchmarks, what is the approximate value of<BR>\n" );
document.write( "a) *square root sign* 42<BR>\n" );
document.write( "b)  3 *square root sign* 50 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #633823 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=633823\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'm not sure what is meant by \"benchmarks\".  I'm guessing some sort of Common Core math?\r<BR>\n" );
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document.write( "The square root of 42 is 6.48<BR>\n" );
document.write( "You could look at the square of 6 (36) and the square of 7 (49) and guess that it's pretty close to halfway between.<BR>\n" );
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document.write( "3 sqrt 50 = 21.21<BR>\n" );
document.write( "Again, you could estimate that the square root of 50 is going to be just over 7 (since 7*7 = 49).  Then multiply that by 3.  Your estimate would be \"just over 21.\"  The \"benchmark\" would be 7 squared, I guess.<BR>\n" );
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document.write( "If this is not what you're after, please clarify and repost. </SPAN>\n" );
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