document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1017542>Question 1017542</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A train leaves New Orleans at 2:00 PM. A second train leaves the same city in the same direction at 4:00 PM. The second train travels 42 mph faster than the first. If the second train overtakes the first at 6:00 PM, what is the speed of each of the two trains? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #633817 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=633817\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A train leaves New Orleans at 2:00 PM. A second train leaves the same city in the same direction at 4:00 PM. The second train travels 42 mph faster than the first. If the second train overtakes the first at 6:00 PM, what is the speed of each of the two trains?<BR>\n" );
document.write( "let x=speed of slower train<BR>\n" );
document.write( "travel time of slower train=6-2=4 hrs<BR>\n" );
document.write( "x+42=speed of faster train<BR>\n" );
document.write( "distance=speed*travel time(same for both trains)<BR>\n" );
document.write( "travel time of faster train=6-4=2 hrs<BR>\n" );
document.write( " 4x=2(x+42) <BR>\n" );
document.write( "4x=2x+84<BR>\n" );
document.write( "2x=84<BR>\n" );
document.write( "x=42<BR>\n" );
document.write( "x+42=84  <BR>\n" );
document.write( "speed of slower train= 84 mph<BR>\n" );
document.write( "speed of faster train=42 mph  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );