document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1017531>Question 1017531</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The Hypotenuse of a right angled triangle is 25cm long if the other two sides are such that the length of one side is 5cm more than the length of one side find the length of the two sides </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #633803 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=633803\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a^2 + b^2 = c^2 where c is the hypotenuse<BR>\n" );
document.write( "a = b+5<BR>\n" );
document.write( "Now your equation is<BR>\n" );
document.write( "(b+5)^2 + b^2 = 625<BR>\n" );
document.write( "b^2 +10b +25 +b^2 = 625<BR>\n" );
document.write( "2b^2 + 10b +25 = 625<BR>\n" );
document.write( "2b^2 +10b -600= 0<BR>\n" );
document.write( "b^2 +5b -300 = 0<BR>\n" );
document.write( "b = -15,20<BR>\n" );
document.write( "Obviously there's no negative in measurement so ignore the sign.  The sides are 15 and 20<BR>\n" );
document.write( "15^2 + 20^2 = 25^2<BR>\n" );
document.write( "225 + 400 = 625<BR>\n" );
document.write( " </SPAN>\n" );
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