document.write( "Question 1017308: Samantha invests a total of $33,500 in two accounts paying 13% and 7% simple interest, respectively. How much was invested in each account if, after one year, the total interest was $3,455.00.
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Algebra.Com's Answer #633777 by ankor@dixie-net.com(22740)\"\" \"About 
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Samantha invests a total of $33,500 in two accounts paying 13% and 7% simple interest, respectively.
\n" ); document.write( " How much was invested in each account if, after one year, the total interest was $3,455.00.
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\n" ); document.write( "let x - amt invested at 13%
\n" ); document.write( "The total amt invested was 33500, therefore
\n" ); document.write( "(33500 - x) = amt invested at 7%
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\n" ); document.write( ".13x + .07(33500-x) = 3455
\n" ); document.write( ".13x + 2345 - .07x = 3455
\n" ); document.write( ".13x - .07x = 3455 - 2345
\n" ); document.write( ".06x = 1110
\n" ); document.write( "x = 1110/.06
\n" ); document.write( "x = $18,500 invested a 13%
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\n" ); document.write( "Find how much invested at 7%
\n" ); document.write( "33500 - 18500= $15,000 invested at 7%
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\n" ); document.write( "Check this find the sum actual interest from each investment
\n" ); document.write( ".13(18500) = 2405
\n" ); document.write( ".07(15000) = 1050
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\n" ); document.write( "total int: 3455
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