document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1017486>Question 1017486</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Please Help me I never was good at word problem. Please show all work.<BR>\n" );
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document.write( " The length of a rectangular garden is 7 feet longer than its width. If the garden's perimeter is 202 feet, what is the area of the garden in square feet? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #633769 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=633769\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You just have to be able to translate it into an algebra problem.\r<BR>\n" );
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document.write( "\"The length of a rectangular garden is 7 feet longer than its width\"<BR>\n" );
document.write( "This means that L = W+7, where L and W are the length and width, in ft.\r<BR>\n" );
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document.write( "\"If the garden's perimeter is 202 feet\"<BR>\n" );
document.write( "So 2L + 2W = 202.\r<BR>\n" );
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document.write( "\"what is the area of the garden in square feet?\"<BR>\n" );
document.write( "This asks you to find L*W.\r<BR>\n" );
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document.write( "So L = W+7, so substituting that into the perimeter equation, we get 2(W+7) + 2W = 202. Can you solve for W and L?\r<BR>\n" );
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