document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1017452>Question 1017452</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An architect designs a rectangular flower garden such that the width is exactly two-thirds of the length. If 210 ft of fencing are to be used to enclose the garden, find the dimensions of the garden.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #633750 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=633750\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter P = 2L + 2W = 210.<BR>\n" );
document.write( "Here W = (2/3)L.<BR>\n" );
document.write( "Plugging that in we get<BR>\n" );
document.write( "2L + 2(2/3)L = 210<BR>\n" );
document.write( "2L + (4/3)L = 210<BR>\n" );
document.write( "(10/3)L = 210<BR>\n" );
document.write( "Multiply by 3/10 and get<BR>\n" );
document.write( "L = 63 ft<BR>\n" );
document.write( "W = (2/3)(63) = 42 ft </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );