document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1017385>Question 1017385</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Cesar is 101 years old. Taylor is 41 years old. How many years ago was Cesar's age 4 times Taylor's age? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #633747 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=633747\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the number of years ago you want, x.  Then we write<BR>\n" );
document.write( "101 - x = 4(41 - x)<BR>\n" );
document.write( "101 - x = 164 - 4x<BR>\n" );
document.write( "3x = 63<BR>\n" );
document.write( "x = 21 years ago<BR>\n" );
document.write( "They were 80 and 20. </SPAN>\n" );
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