document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1017347>Question 1017347</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 9/11x - 3 = -5/11x - 6\r<BR>\n" );
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document.write( "x=99/14\r<BR>\n" );
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document.write( "I think I am getting lost in the computation<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #633739 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=633739\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay, from<BR>\n" );
document.write( "(9/11)x - 3 = (-5/11)x - 6<BR>\n" );
document.write( "let us add (5/11)x to both sides, then add three to both sides and get<BR>\n" );
document.write( "(14/11)x - 3 = -6<BR>\n" );
document.write( "(14/11)x = -3<BR>\n" );
document.write( "Now multiply both sides by the reciprocal of 14/11, which is 11/14...we get<BR>\n" );
document.write( "x = -3(11/14) = -33/14 </SPAN>\n" );
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