document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1017376>Question 1017376</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Lee’s mother was 3 times Lee’s age six years ago. Now Lee’s mother is 28 years older than<BR>\n" );
document.write( "Lee. What is Lee’s age now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #633727 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=633727\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call Mom's and Lee's age NOW, M and L.<BR>\n" );
document.write( "Then we can write<BR>\n" );
document.write( "M - 6 = 3(L - 6)  and<BR>\n" );
document.write( "M = L + 28<BR>\n" );
document.write( "Substitute this into the first equation and get<BR>\n" );
document.write( "L+28 - 6 = 3(L - 6)<BR>\n" );
document.write( "L + 22 = 3L - 18<BR>\n" );
document.write( "Add 18 and subtract L from both sides and get<BR>\n" );
document.write( "L + 40 = 3L<BR>\n" );
document.write( "40 = 2L<BR>\n" );
document.write( "L = 20 years old NOW. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );