document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1017383>Question 1017383</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the first three terms of a geometric sequence are: T1:T2:T3. if T2=T1+4 and T3=T2+9, determine the value of T1:T2:T3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #633716 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=633716\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If that is so, then the ratio of T2 to T1 = the ratio of T3 to T2, or<BR>\n" );
document.write( "T2/T1 = T3/T2<BR>\n" );
document.write( "T2/(T2-4) = (T2+9)/T2<BR>\n" );
document.write( "Let us call T2, x, for simplicity...now cross-multiply and get<BR>\n" );
document.write( "x^2 = (x-4)(x+9)<BR>\n" );
document.write( "x^2 = x^2 + 5x - 36<BR>\n" );
document.write( "0 = 5x - 36<BR>\n" );
document.write( "36 = 5x<BR>\n" );
document.write( "x = T2 = 7.2<BR>\n" );
document.write( "T1 = 3.2<BR>\n" );
document.write( "T3 = 16.2<BR>\n" );
document.write( "so that<BR>\n" );
document.write( "T1:T2:T3 = 3.2:7.2:16.2 = 16:36:81 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );