document.write( "Question 1017321: Julie and Eric row their boat (at constant speed ) 40 miles downstream for 4 hours, helped by the current. Rowing at the same rate, the trip back against the current takes 10 hours. Find the rate of the current. \n" ); document.write( "
Algebra.Com's Answer #633661 by MathTherapy(10556)\"\" \"About 
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\n" ); document.write( "Julie and Eric row their boat (at constant speed ) 40 miles downstream for 4 hours, helped by the current. Rowing at the same rate, the trip back against the current takes 10 hours. Find the rate of the current.
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Let speed in still water be S, and speed of current, C
\n" ); document.write( "Then, downstream speed equation is: \"S+%2B+C+=+40%2F4\"______S + C = 10______S = 10 - C ------- eq (i)
\n" ); document.write( "Also, upstream speed equation is: \"S+-+C+=+40%2F10\"______S - C = 4 ------- eq (ii)
\n" ); document.write( "10 - C - C = 4 ------- Substituting 10 - C for S in eq (ii)
\n" ); document.write( " - 2C = 4 - 10
\n" ); document.write( " - 2C = - 6
\n" ); document.write( "C or speed of current = \"%28-+6%29%2F%28-+2%29\", or \"highlight_green%28matrix%281%2C2%2C3%2Cmph%29%29\" \n" ); document.write( "
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