document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1017368>Question 1017368</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles of a polygon are right angle and the remaining are 120 each.find the no. Of sides in it<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #633649 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=633649\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two angles of a polygon are right angle and the remaining are 120 each.find the no. Of sides in it<BR>\n" );
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document.write( "Sum of angles = 2*90 + (n-2)*120<BR>\n" );
document.write( "Sum = 180*(n-2) = 180 + n*120 - 240<BR>\n" );
document.write( "180n - 360 = 120n - 60<BR>\n" );
document.write( "60n = 300<BR>\n" );
document.write( "n = 5\r<BR>\n" );
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