document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=87426>Question 87426</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the sum of the first 10 terms of the series 6.4, 3.2, 1.6, ... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #63360 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=63360\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the sum of the first 10 terms of the series 6.4, 3.2, 1.6, ...<BR>\n" );
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document.write( "r = 3/2/6.4 = 1/2<BR>\n" );
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document.write( "S(10) = 6.4[(1/2)^11 -1)/((1/2)-1)]<BR>\n" );
document.write( "S(10) = 6.4[-0.9995117/-0.5] = 12.79375\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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