document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1017291>Question 1017291</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a triangle is 74 inches. The second side is 2 inches more than twice the first side, and the third side is 6 inches less than three times the first side. Find the lengths of the three sides of the triangle. \r<BR>\n" );
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document.write( "Length of Sides (in inches) (separate with commas): </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #633593 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=633593\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's call the first side x. <BR>\n" );
document.write( "Then, the problem says:<BR>\n" );
document.write( "The second side is 2 inches more than twice the first side:<BR>\n" );
document.write( "Second side = 2x+2<BR>\n" );
document.write( "and the third side is 6 inches less than three times the first side:<BR>\n" );
document.write( "Third side = 3x-6<BR>\n" );
document.write( "The perimeter is the sum of the lengths of all sides, so in this case we get:<BR>\n" );
document.write( "x+2x+2+3x-6 = 74 Add all x on left and also add 2 and -6:<BR>\n" );
document.write( "6x-4 = 74 Add 4 on both sides<BR>\n" );
document.write( "6x = 78 Divide both sides by 4:<BR>\n" );
document.write( "x = 13 is the first side<BR>\n" );
document.write( "Second side 2(13)+2<BR>\n" );
document.write( "Third side 3(13)-6<BR>\n" );
document.write( "Use your calculator.<BR>\n" );
document.write( "J </SPAN>\n" );
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