document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1017136>Question 1017136</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 4 inches longer than its width.  If the perimeter of the rectangle is 76&#8203; inches, find the length </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #633493 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=633493\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter P = 2L + 2W = 76 and <BR>\n" );
document.write( "L = W + 4<BR>\n" );
document.write( "Now substitute and get<BR>\n" );
document.write( "2(W+4) + 2W = 76<BR>\n" );
document.write( "2W + 8 + 2W = 76<BR>\n" );
document.write( "4W + 8 = 76<BR>\n" );
document.write( "4W = 68<BR>\n" );
document.write( "W = 17 inches<BR>\n" );
document.write( "L = W + 4 = 21 inches </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );