document.write( "Question 1017087: Betty had 4 times as much money as cathy.After Betty had spend $12 and Cathy had received $6,they had the same amount of money .How much money had each of them at first. \n" ); document.write( "

Algebra.Com's Answer #633459 by addingup(3677) $\"\"$ $\"About$

You can put this solution on YOUR website!
B= 4C Note that the problem is telling us that B= 4C. We will use this value for B next:
\n" ); document.write( "B-12 = C+6 Substitute for B:
\n" ); document.write( "4C-12 = C+6 Add 12 on both sides
\n" ); document.write( "4C = C+18 Subtract C on both sides:
\n" ); document.write( "3C = 18 Divide both sides by 3:
\n" ); document.write( "C = 6 So Cathy had 6, and Betty 4 times more:
\n" ); document.write( "B = 6*4 = 24
\n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
\n" ); document.write( "The problem says that \"after Betty had spend $12 and Cathy had received $6,they had the same amount of money\" Let's see if we have the right answers:
\n" ); document.write( "B: 24-12=12
\n" ); document.write( "C: 6+ 6 =12
\n" ); document.write( "We have the correct answer \n" ); document.write( "

\n" );