document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1017094>Question 1017094</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find k so that the minimum value of f(x) =x^2 +kx+8 is equal to the maximum value of g(x) = 1 +4x-2x^2. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #633451 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=633451\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Find k so that the minimum value of f(x) =x^2 +kx+8 is equal to the maximum value of g(x) = 1 +4x-2x^2. <BR>\n" );
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document.write( "Note:: Max or Min occurs at -b(2a)<BR>\n" );
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document.write( "min of f(x) at (-k/2,f(-k/2))<BR>\n" );
document.write( "max of g(x) at (-4/-4,g(1))<BR>\n" );
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document.write( "Solve::<BR>\n" );
document.write( "f(-k/2) = g(1)<BR>\n" );
document.write( "(-k/2)^2 + k(-k/2) + 8 = 1 + 4 - 2<BR>\n" );
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document.write( "k^2/4 - k^2/2 + 5 = 0<BR>\n" );
document.write( "k^2 - 2k^2 + 20 = 0<BR>\n" );
document.write( "k^2 = 20<BR>\n" );
document.write( "k = 2sqrt(5)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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