document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1017070>Question 1017070</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the ages of a gold coin and a silver coin is 60 years. The age of the gold coin 10 years from now will be 5 years less than the age of the silver coin 15 years ago. Find the present ages of the two coins. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #633406 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=633406\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> g+s = 60 subtract s from both sides: g= 60-s<BR>\n" );
document.write( "g+10 = s-15+5 substitute for g:<BR>\n" );
document.write( "60-s+10 = s-15+5<BR>\n" );
document.write( "70-s = s-20 Add 20 and s, both sides<BR>\n" );
document.write( "90 = 2s Divide both sides by 2:<BR>\n" );
document.write( "45 = s so this is the age of the silver coin, and the gold:<BR>\n" );
document.write( "60-45= 15 is the age of the gold coin<BR>\n" );
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