document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1017069>Question 1017069</A>: <I><SPAN STYLE=\"word-break: break-all;\"> an equilateral triangle and a rectangle have the same perimeter. the length of a rectangle is 3 cm less tan twice the width. each side of a triangle is 12 cm. find the area of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #633403 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=633403\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of the triangle is 12*3=36. And the rectangle has the same perimeter.<BR>\n" );
document.write( "and the problem tells us that the length of the rectangle is:<BR>\n" );
document.write( "L = 2W-3<BR>\n" );
document.write( "Now, the perimeter of the rectangle is:<BR>\n" );
document.write( "2L+2W = 36 Substitute for L:<BR>\n" );
document.write( "2(2W-3)+2W = 36<BR>\n" );
document.write( "4W-6+2W = 36<BR>\n" );
document.write( "6W-6 = 36 Add 6, both sides:<BR>\n" );
document.write( "6W = 42 Divide both sides by 6<BR>\n" );
document.write( "W = 7 This is the width. And the length:<BR>\n" );
document.write( "L= 2W-3 = 2(7)-3 = 14-3 = 11 is the length<BR>\n" );
document.write( "J<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );