document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=87409>Question 87409</A>: <I><SPAN STYLE=\"word-break: break-all;\"> rewrite3 the middle term as the sum of two terms and then factor completely:<BR>\n" );
document.write( "9x^2-9x-10 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #63339 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=63339\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> rewrite3 the middle term as the sum of two terms and then factor completely:<BR>\n" );
document.write( "9x^2-9x-10<BR>\n" );
document.write( "This is called the AC Method of factoring.<BR>\n" );
document.write( "Think of two numbers whose product is AC = -10*9 = -90<BR>\n" );
document.write( "and whose sum is B = -9<BR>\n" );
document.write( "The numbers are -15 and +6<BR>\n" );
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document.write( "Rewrite the problems with the sum replacing the 2nd term:<BR>\n" );
document.write( "9x^2-15x+6x-10<BR>\n" );
document.write( "----------<BR>\n" );
document.write( "Factor the 1st two and the last two terms separately to get:<BR>\n" );
document.write( "3x(3x-5)+2(3x-5)<BR>\n" );
document.write( " <BR>\n" );
document.write( "=(3x-5)(3x+2)\r<BR>\n" );
document.write( "\n" );
document.write( "================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );