document.write( "Question 1016990: an infinite geometric series with second term -8/9 and sum 2. what is the first term? \n" ); document.write( "
Algebra.Com's Answer #633379 by ikleyn(52794)\"\" \"About 
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\n" ); document.write( "an infinite geometric series with second term -8/9 and sum 2. what is the first term?
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document.write( "a*r = \"-8%2F9\"    (1)    This is your first equation for the second term of GP.\r\n" );
document.write( "                     Here \"a\"is the first term and \"r\" is the common ratio of the GP.\r\n" );
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document.write( "\"a%2F%281-r%29\" = 2    (2)    This is your second equation for the sum.\r\n" );
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document.write( "From the first equation express r = \"-8%2F%289a%29\" and substitute it into the second equation. You will get\r\n" );
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document.write( "\"a%2F%281+-+%28%28-8%29%2F%289a%29%29%29%29\" = 2,   or\r\n" );
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document.write( "\"a\" = \"2%2A%281+%2B+%288%2F%289a%29%29%29\",   or\r\n" );
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document.write( "\"a\" = \"2+%2B+16%2F%289a%29\".\r\n" );
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document.write( "Now multiply both sides by 9a. You will get\r\n" );
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document.write( "\"9a%5E2\" = 18a + 16,   or \r\n" );
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document.write( "\"9a%5E2+-+18a+-+16\" = \"0\".\r\n" );
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document.write( "Apply the quadratic formula to solve this quadratic equation. You will get\r\n" );
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document.write( "two roots \"a%5B1%5D\" = \"8%2F3\" and \"a%5B2%5D\" = -\"2%2F3\".\r\n" );
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document.write( "The values of \"r\" that correspond to these values of \"a\" in accordance to (1), are\r\n" );
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document.write( "\"r%5B1%5D\" = \"%28-8%2F9%29\" : \"8%2F3\" = \"-1%2F3\"  and  \"r%5B2%5D\" = \"%28-8%2F9%29\" : \"%28-2%2F3%29\" = \"4%2F3\".\r\n" );
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document.write( "The second \"r%5B2%5D\" = \"4%2F3\" has the modulus greater than 1 and therefore generates the \"divergent\" geometric progression. So, the second solution doesn't fit.\r\n" );
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document.write( "Now check the equality (2) for the first solution: \"a%5B1%5D%2F%281-r%5B1%5D%29\" = \"8%2F3\" : \"%281-%28-1%2F3%29%29\" = \"8%2F3\" : \"%281+%2B+1%2F3%29\" = \"8%2F3\" : \"4%2F3\" = 2.  OK!\r\n" );
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document.write( "Thus there is a unique GP with the given second term and the given sum.\r\n" );
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document.write( "It is  \"a%5B1%5D\" =  \"8%2F3\",  \"r%5B1%5D\" = \"-1%2F3\".\r\n" );
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