document.write( "Question 1017034: Paul is 102 years younger than Alicia. 2 years ago, Alicia's age was 4 times Paul's age. How old is Paul now?
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Algebra.Com's Answer #633353 by JulietG(1812)![]() ![]() You can put this solution on YOUR website! Alicia must eat very healthy! \n" ); document.write( "P = A-102 \n" ); document.write( "A-2 = 4(P-2) \n" ); document.write( "A-2 = 4P-8 \n" ); document.write( "A = 4P-6 \n" ); document.write( "Substitute the known value of P \n" ); document.write( "A = 4(A-102)-6 \n" ); document.write( "A = 4A-408-6 \n" ); document.write( "A = 4A-414 \n" ); document.write( "414 = 3A \n" ); document.write( "A = 138 \n" ); document.write( ". \n" ); document.write( "While this is likely impossible, let's plug the numbers in just for kicks. \n" ); document.write( "Paul is 102 years younger than Alicia, who is 138. Therefore Paul is 36. \n" ); document.write( "Two years ago, Paul would have been 36-2, or 34. 4x34 = 136, which is two years younger than Alicia is now. \n" ); document.write( " \n" ); document.write( " |