document.write( "Question 1017034: Paul is 102 years younger than Alicia. 2 years ago, Alicia's age was 4 times Paul's age. How old is Paul now?
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Algebra.Com's Answer #633353 by JulietG(1812)\"\" \"About 
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Alicia must eat very healthy!
\n" ); document.write( "P = A-102
\n" ); document.write( "A-2 = 4(P-2)
\n" ); document.write( "A-2 = 4P-8
\n" ); document.write( "A = 4P-6
\n" ); document.write( "Substitute the known value of P
\n" ); document.write( "A = 4(A-102)-6
\n" ); document.write( "A = 4A-408-6
\n" ); document.write( "A = 4A-414
\n" ); document.write( "414 = 3A
\n" ); document.write( "A = 138
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\n" ); document.write( "While this is likely impossible, let's plug the numbers in just for kicks.
\n" ); document.write( "Paul is 102 years younger than Alicia, who is 138. Therefore Paul is 36.
\n" ); document.write( "Two years ago, Paul would have been 36-2, or 34. 4x34 = 136, which is two years younger than Alicia is now.
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