document.write( "Question 1016986: two planes, which are 3400 miles apart, fly toward each other .their speeds differ by 50mph.if they pass each other in 4 hours, what is the speed of each? \n" ); document.write( "
Algebra.Com's Answer #633330 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "3400 mi/4hrs = 850 mph \n" ); document.write( ". \n" ); document.write( "The combined speeds of both planes is 850 mph. \n" ); document.write( ". \n" ); document.write( "S=speed of slower plane; F=speed of faster plane=S+50 mph \n" ); document.write( ". \n" ); document.write( "S+F=850mph \n" ); document.write( "S+(S+50mph)=850mph \n" ); document.write( "2S=800mph \n" ); document.write( "S=400mph \n" ); document.write( "F=S+50mph=400mph+50mph=450mph \n" ); document.write( ". \n" ); document.write( "ANSWER: The slower plane is traveling 400 mph and the \n" ); document.write( "faster plane is traveling 450 mph. \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |