document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=87307>Question 87307</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. Factor completely.   64x^3-48x^2-4x+3<BR>\n" );
document.write( "   I have came up with 8x^2(8x-6)-4x+3  I don't know what to do with the 4x+3.\r<BR>\n" );
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document.write( "2. Factor completely.   49x^3y-112x^2y^2+64xy^3<BR>\n" );
document.write( "   On this question i have tried using -2,-32; -4,-16; -8,8 to factor but they     aren't working.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #63326 by </B><A HREF=/tutors/aboutme.mpl?userid=rossiv53><B>rossiv53(27)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rossiv53><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=63326\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. Fctor by grouping the first two terms and the last two terms.<BR>\n" );
document.write( "So, (64x^3-48x^2)-(4x-3)<BR>\n" );
document.write( "Factor out common factors..<BR>\n" );
document.write( "This gives you 16x^2(4x-3)-(4x-3)<BR>\n" );
document.write( "Factored form is (16x^2-1)(4x-3)\r<BR>\n" );
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document.write( "2.  Only common factors in second equation are xy.\r<BR>\n" );
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document.write( "This gives you xy(49x^2-112x^2y+64y^2)<BR>\n" );
document.write( "You can factor this further by grouping in the second term.<BR>\n" );
document.write( "xy(49x^2-56xy-56xy+64y^2)<BR>\n" );
document.write( "   7x(7x-8y)-8y(7x-8y)<BR>\n" );
document.write( "So, answer is xy(7x-8y)(7x-8y)or xy(7x-8y)^2\r<BR>\n" );
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document.write( "Good luck. </SPAN>\n" );
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