document.write( "Question 1016895: if a,b are positive numbers such that a+b=1 , prove that a^2+b^2 >= 1/2 \n" ); document.write( "
Algebra.Com's Answer #633240 by robertb(5830)\"\" \"About 
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\"a%5E2+%2B+b%5E2++=+a%5E2+%2B+%281-a%29%5E2+=+2a%5E2+-2a%2B1\"
\n" ); document.write( "Now for any quadratic expression \"Ax%5E2+%2BBx+%2B+C\", the maximum or minimum value is \"C-B%5E2%2F%284AC%29\". In this case, A = 2 >0, and hence we have a minimum value.\r
\n" ); document.write( "\n" ); document.write( "The minimum value of \"2a%5E2+-2a%2B1\" is then equal to \"1-%28-2%29%5E2%2F%284%2A2%2A1%29+=+1+-+4%2F8+=+1%2F2\".\r
\n" ); document.write( "\n" ); document.write( "This ends the solution.
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