document.write( "Question 87368: The length of a rectangular playing field is 5 ft less than twice its width.
\n" ); document.write( "If the perimeter of the playing field is 230 ft, find the length and width of the field
\n" ); document.write( "

Algebra.Com's Answer #63324 by rossiv53(27)\"\" \"About 
You can put this solution on YOUR website!
Ok, so begin by assigning a variable for width.
\n" ); document.write( "Width = W
\n" ); document.write( "We know that length is 5 feet less than twice the width. So, L=2W-5
\n" ); document.write( "Perimeter is equal to the value of all four sides.
\n" ); document.write( "So, W+W+(2W-5)+(2W-5)=230 ft
\n" ); document.write( "2W+2(2W-5)=230
\n" ); document.write( "2W+4W-10=230
\n" ); document.write( "6W-10=230
\n" ); document.write( "6W-10+10=230+10
\n" ); document.write( "6W=240
\n" ); document.write( "W=40 This is width
\n" ); document.write( "L=2(40)-5
\n" ); document.write( "L=75
\n" ); document.write( "75+75+40+40=230ft \r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );