document.write( "Question 1016790: a patio is configured from a rectangle with two right triangles of equal size attached at the two ends.The length of the rectangle is 38 ft. The base of the right triangle is 4 ft less than the height of the triangle. If the total area of the patio is 1155 ft^2 determine the base and height of the triangular portions \n" ); document.write( "
Algebra.Com's Answer #633215 by ankor@dixie-net.com(22740)\"\" \"About 
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a patio is configured from a rectangle with two right triangles of equal size attached at the two ends.
\n" ); document.write( " The length of the rectangle is 38 ft.
\n" ); document.write( " The base of the right triangle is 4 ft less than the height of the triangle.
\n" ); document.write( " If the total area of the patio is 1155 ft^2 determine the base and height of the triangular portions
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\n" ); document.write( "The way I see this, the height of the right triangle is also the width of the rectangle.
\n" ); document.write( "h = the height of the triangle and the width of the rectangle
\n" ); document.write( "(h-4) = base of the triangle
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\n" ); document.write( "The two right triangles form a rectangle whose area is h(h-4)
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\n" ); document.write( "An equivalent rectangle is formed with length of (h-4) + 38 = (h+34); width = h
\n" ); document.write( "Total area
\n" ); document.write( "h(h+34) = 1155
\n" ); document.write( "h^2 + 34h - 1155 = 0; a quadratic equation; a=1; b=34; c=-1155
\n" ); document.write( "Using the quadratic formula, the positive solution
\n" ); document.write( "h = 21 ft is the height of the triangle
\n" ); document.write( "and
\n" ); document.write( "21-4 = 17 ft is the base of the triangle
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\n" ); document.write( "Check this, find the area of the rectangular section and the 2 triangles
\n" ); document.write( "38 * 21 = 798 sq/ft
\n" ); document.write( "17 * 21 = 357
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\n" ); document.write( "total area: 1155 \n" ); document.write( "
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