document.write( "Question 1016841: (v^2 - 4v)^2 - 17(v^2 - 4v) +60 = 0\r
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document.write( "This is what I have so far? Not sure where I went wrong.\r
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document.write( "let v = v^2 - 4v\r
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document.write( "v^2 - 17v +60 = 0
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document.write( "(v-12)(v-5) = 0
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document.write( "v-12 = 0 or v-5 = 0
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document.write( "v=12 or v=5
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document.write( "v^2 = 12 or v^2 = 5
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document.write( "√v^2 = =-√12 or √v^2 = +-√5
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document.write( "v = +-2√3 or v = +-√5 \n" );
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Algebra.Com's Answer #633213 by richard1234(7193)![]() ![]() You can put this solution on YOUR website! You should use a different letter than \"v\" for your substitutions since it is already a variable name (say \"u = v^2 - 4v\").\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The mistake comes where you say \"u=12 or u=5\" and the next line is \"v^2 = 12 or v^2 = 5.\" Should be \"v^2 - 4v = 12 or \"v^2 - 4v = 5.\" \n" ); document.write( " |