document.write( "Question 87379: The length of the rectangle is 3 times its width. The perimeter of the rectangle is 160 ft. Find the length and the width of the rectangle. Solve the problem algebraically. \n" ); document.write( "
Algebra.Com's Answer #63319 by Nate(3500)\"\" \"About 
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width = w
\n" ); document.write( "length = 3w
\n" ); document.write( "2*width + 2*length = perimeter
\n" ); document.write( "2(w) + 2(3w) = 160
\n" ); document.write( "2w + 6w = 160
\n" ); document.write( "8w = 160
\n" ); document.write( "w = 20
\n" ); document.write( "width = 20 feet
\n" ); document.write( "length = 60 feet
\n" ); document.write( "
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