document.write( "Question 1016806: Last year Rachel invested money in two accounts. The first account had an interest rate of 6% and the second account had an interest rate of 4%. If she invested $300 more in the first account than the second and her total interest income was $608, how much did she invest at each rate?
\n" ); document.write( "Step 1 of 3 : Complete the following table by entering the missing values. Enter the rates in decimal for
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Algebra.Com's Answer #633184 by stanbon(75887)\"\" \"About 
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Last year Rachel invested money in two accounts. The first account had an interest rate of 6% and the second account had an interest rate of 4%. If she invested $300 more in the first account than the second and her total interest income was $608, how much did she invest at each rate?
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\n" ); document.write( "Equations:
\n" ); document.write( "s = f + 300 dollars
\n" ); document.write( "0.06s + 0.04f = 608 dollars
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\n" ); document.write( "Modify for elimination::
\n" ); document.write( "6s - 6f = 6*300
\n" ); document.write( "6s + 4f = 100*608
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\n" ); document.write( "Subtract and solve for \"f\"::
\n" ); document.write( "10f = 59000
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\n" ); document.write( "f = $5900.00 (amt invested at 4%)
\n" ); document.write( "s = f+300 = $59,300 (amt invested at 6%)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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