document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1016800>Question 1016800</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3 feet less than twice its width and the perimeter is 72 feet.  Find the length and the width  of the rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #633175 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=633175\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3 feet less than twice its width and the perimeter is 72 feet. Find the length and the width of the rectangle <BR>\n" );
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document.write( "length:: 2w - 3<BR>\n" );
document.write( "width::: w<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "p = 2(length + width)<BR>\n" );
document.write( "72 = 2(3w-3)<BR>\n" );
document.write( "Divide both sides by 2 to get::<BR>\n" );
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document.write( "3w-3 = 36<BR>\n" );
document.write( "width = 13 ft.<BR>\n" );
document.write( "length = 2w-3 = 23 ft<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "------------<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );