document.write( "Question 1016704: 1) The sum of the ages of Luis and Shannon is 108 years. 9 years ago, Luis's age was 4 times Shannon's age. How old is Luis now?\r
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document.write( "2) Jason is 80 years old. Erin is 35 years old. How many years until Jason's age is 2 times Erin's age? years \n" );
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Algebra.Com's Answer #633167 by macston(5194) You can put this solution on YOUR website! . \n" ); document.write( "L=Luis's age; S=Shannon's age \n" ); document.write( ". \n" ); document.write( "L+S=108 \n" ); document.write( "L=108-S \n" ); document.write( ". \n" ); document.write( "L-9=4(S-9) \n" ); document.write( "L-9=4S-36 \n" ); document.write( "L=4S-27 \n" ); document.write( "108-S=4S-27 \n" ); document.write( "135=5S \n" ); document.write( "45=27 \n" ); document.write( ". \n" ); document.write( "L=108-S=108-27=81 \n" ); document.write( ". \n" ); document.write( "ANSWER: Luis is 81 and Shannon is 27. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "L-9=4(S-9) \n" ); document.write( "81-9=4(27-9) \n" ); document.write( "72=4(18) \n" ); document.write( "72=72 \n" ); document.write( ".\r \n" ); document.write( "\n" ); document.write( "LIMIT ONE QUESTION PER POST. \n" ); document.write( " \n" ); document.write( " |