document.write( "Question 1016704: 1) The sum of the ages of Luis and Shannon is 108 years. 9 years ago, Luis's age was 4 times Shannon's age. How old is Luis now?\r
\n" ); document.write( "\n" ); document.write( "2) Jason is 80 years old. Erin is 35 years old. How many years until Jason's age is 2 times Erin's age? years
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Algebra.Com's Answer #633167 by macston(5194)\"\" \"About 
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\n" ); document.write( "L=Luis's age; S=Shannon's age
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\n" ); document.write( "L+S=108
\n" ); document.write( "L=108-S
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\n" ); document.write( "L-9=4(S-9)
\n" ); document.write( "L-9=4S-36
\n" ); document.write( "L=4S-27
\n" ); document.write( "108-S=4S-27
\n" ); document.write( "135=5S
\n" ); document.write( "45=27
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\n" ); document.write( "L=108-S=108-27=81
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\n" ); document.write( "ANSWER: Luis is 81 and Shannon is 27.
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\n" ); document.write( "CHECK:
\n" ); document.write( "L-9=4(S-9)
\n" ); document.write( "81-9=4(27-9)
\n" ); document.write( "72=4(18)
\n" ); document.write( "72=72
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\n" ); document.write( "\n" ); document.write( "LIMIT ONE QUESTION PER POST.
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