document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1016659>Question 1016659</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you find the average rate of change for f(x)=x^3-7x+1 from -4 to -2 then -1 to 1 and 1 to 3 thank you I have no example of this </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #633069 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=633069\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do you find the average rate of change for f(x)=x^3-7x+1 from -4 to -2<BR>\n" );
document.write( "Find f(-2)<BR>\n" );
document.write( "Subtract f(-4)<BR>\n" );
document.write( "Divide by 2 (-4 to -2 = 2)<BR>\n" );
document.write( "f(x)=x^3-7x+1<BR>\n" );
document.write( "f(-2) = -8 + 14 + 1 = 7<BR>\n" );
document.write( "f(-4) = -64 + 28 + 1 = -35<BR>\n" );
document.write( "---<BR>\n" );
document.write( "f(-2) - f(-4) = 42<BR>\n" );
document.write( "42/2 = 21<BR>\n" );
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document.write( "Do the same way.<BR>\n" );
document.write( " then -1 to 1 and 1 to 3<BR>\n" );
document.write( " </SPAN>\n" );
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