document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1016661>Question 1016661</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This is a self written problem because I wanted to explore things myself, so here it is:\r<BR>\n" );
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document.write( "Given the two points P(0,1) and Q(3,4)\r<BR>\n" );
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document.write( "I solved for the slope, which was m= -1\r<BR>\n" );
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document.write( "I plugged that into the point-slope formula a received the slope-intercept equation of the line:\r<BR>\n" );
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document.write( "y=-x+1\r<BR>\n" );
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document.write( "but when I plug in the original points to see if they are actually part of the line, point Q(3,4) doesn't work. \r<BR>\n" );
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document.write( "I'm not sure why that happened. I see that point P(0,1) is actually where the graph crosses or touches the graph, but it doesn't make sense that point Q(3,4) isn't on the graph. \r<BR>\n" );
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document.write( "Any suggestions or help would be helpful. \r<BR>\n" );
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document.write( "Edit: I solved it. :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #633066 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=633066\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The slope is actually (4-1)/(3-0) = 3/3 = 1, not -1.<BR>\n" );
document.write( "Thus your line is<BR>\n" );
document.write( "y = x + 1 </SPAN>\n" );
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