document.write( "Question 1016612: Gloria makes teddy bears. She dresses some as girl bears with dresses and bows, and some as boy bears with bow ties. She is running low on supplies. She has only 100 eyes, 30 dresses, and 60 ties that can be sued as bows on the girls and bow ties on the boys.\r
\n" ); document.write( "\n" ); document.write( "How do we write the inequalities for this question?\r
\n" ); document.write( "\n" ); document.write( "Many thanks
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Algebra.Com's Answer #633042 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+b+\" = number of boy bears that can be made
\n" ); document.write( "Let \"+g+\" = number of girl bears that can be made
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\n" ); document.write( "(1) \"+g+%3C=+30+\"
\n" ); document.write( "You can't have more girl bears than dresses for them
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\n" ); document.write( "\"+b+%2B+g+%3C=+100%2F2+\"
\n" ); document.write( "(2) \"+b+%2B+g+%3C=+50+\"
\n" ); document.write( "Total number of bears can't be more than the
\n" ); document.write( "pairs of eyes
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\n" ); document.write( "(3) \"+b+%2B+g+%3C=+60+\"
\n" ); document.write( "Total number of bears can't be more than the
\n" ); document.write( "number of bows
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\n" ); document.write( "(2) is the tighter restriction, so it rules
\n" ); document.write( "Also, I can subtract (1) from (2)
\n" ); document.write( "(2) \"+b+%2B+g+%3C=+50+\"
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\n" ); document.write( "From (1) and (2),
\n" ); document.write( "\"+b+%3C=+20+\"
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