document.write( "Question 1016608: 1/3x + 1/2y + 1/2z = -1
\n" );
document.write( "1/5x - 1/3y + 1/4z = -1/3
\n" );
document.write( "1/2x + 1/ y + 1/2z = -1/2 \n" );
document.write( "
Algebra.Com's Answer #633036 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! 1/3x + 1/2y + 1/2z = -1 \n" ); document.write( "--------- \n" ); document.write( "Is it 1/(3x) ? \n" ); document.write( "Or (1/3)x ? \n" ); document.write( "=================== \n" ); document.write( "1/5x - 1/3y + 1/4z = -1/3 \n" ); document.write( "1/2x + 1/ y + 1/2z = -1/2 \n" ); document.write( " |