document.write( "Question 1016592: Compute the density in g/cm3 of a piece of metal that has a mass of 0.505 kg and a volume of 53 cm3. \n" ); document.write( "
Algebra.Com's Answer #632963 by FrankM(1040)\"\" \"About 
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We have -\r
\n" ); document.write( "\n" ); document.write( "\".505kg%2F53cc\" and we want \"g%2Fcc\"\r
\n" ); document.write( "\n" ); document.write( "In between we need to multiply to cancel what we don't want, and get what we want - \r
\n" ); document.write( "\n" ); document.write( "\"1000g%2Fkg\"\r
\n" ); document.write( "\n" ); document.write( "is the missing units' conversion. This process is called dimensional analysis. Let's finish the problem -\r
\n" ); document.write( "\n" ); document.write( "\"%28.505kg%2F53cc%29%2A%281000g%2Fkg%29+=+9.528g%2Fcc\" \r
\n" ); document.write( "\n" ); document.write( "In this case the kg cancel and leave the g we want. It's key to use \"1000g%2Fkg\" with 1000g on top, and 1 kg below. If you flip by mistake, you'd get \"kg%5E2\" up top. That's a hint there's a mistake. The numbers follow units.
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