document.write( "Question 1016476: Alfred has 62 coins totaling $11.15 in nickels, dimes, and quarters. If he has 30 cents in nickels, how many of each coin does he have? \n" ); document.write( "
Algebra.Com's Answer #632867 by FrankM(1040)\"\" \"About 
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30 cents in nickels is 6 coins. \r
\n" ); document.write( "\n" ); document.write( "The problem reduces to 56 coins, $10.85 in dimes and quarters. \r
\n" ); document.write( "\n" ); document.write( "10D+25Q= 1085\r
\n" ); document.write( "\n" ); document.write( "D+Q=56 (multiply by 10)\r
\n" ); document.write( "\n" ); document.write( "10D+10Q=560\r
\n" ); document.write( "\n" ); document.write( "15Q= 525\r
\n" ); document.write( "\n" ); document.write( "Q=35\r
\n" ); document.write( "\n" ); document.write( "D = 21\r
\n" ); document.write( "\n" ); document.write( "Check, 35 quarters are $8.75
\n" ); document.write( "21 dimes is $2.10\r
\n" ); document.write( "\n" ); document.write( "Adds to $10.85\r
\n" ); document.write( "\n" ); document.write( "And remember 6 nickels. \r
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