document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1016447>Question 1016447</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Harry is X years old. Three years ago Jenny was twice as old. In three years time Ahmed will be 5 times as old as Jenny. Write an expression for Ahmed's age </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #632839 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=632839\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Harry is x now.<BR>\n" );
document.write( "Jenny is j now.<BR>\n" );
document.write( "Ahmed is a now.<BR>\n" );
document.write( "j-3 = 2(x-3)  which means j = 2x - 6 + 3 = 2x - 3<BR>\n" );
document.write( "In three years, <BR>\n" );
document.write( "a + 3 = 5(j + 3)<BR>\n" );
document.write( "now solve for a substituting in we get<BR>\n" );
document.write( "a = 5(2x - 3 + 3) - 3 = 10x - 3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );