document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1016395>Question 1016395</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has two solutions of H2SO4. One has a 40% concentration and the other has a 25% concentration. How many liters of each solution must be mixed to obtain 128 liters of a 34% solution?\r<BR>\n" );
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document.write( "Thank you. <BR>\n" );
document.write( "--Will </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #632792 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=632792\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the amount of 40% solution, x.<BR>\n" );
document.write( "Then the amount of 25% used is 128 - x.<BR>\n" );
document.write( "The set up looks like this:<BR>\n" );
document.write( "x(.40) + (128-x)(.25) = 128(.34)<BR>\n" );
document.write( ".4x + 32 - .25x = 43.52<BR>\n" );
document.write( ".15x = 11.52<BR>\n" );
document.write( "x = 11.52/.15 = 76.8 liters of 40% solution<BR>\n" );
document.write( "128-x = 51.2 L of 25% solution </SPAN>\n" );
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