document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1016367>Question 1016367</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can I get help with this question please.\r<BR>\n" );
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document.write( "3/x-8; g(x)=1/x and solve for (fof)(x)\r<BR>\n" );
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document.write( "Thank you so much </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #632769 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=632769\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (f o f)(x)=<BR>\n" );
document.write( "3/(3/x-8) -8<BR>\n" );
document.write( "The denominator is<BR>\n" );
document.write( "[3- 8(x-8)]/x-8, putting everything over (x-8) as a common denominator<BR>\n" );
document.write( "=(-8x+67)/(x-8)<BR>\n" );
document.write( "3/(-8x+67)/(x-8)=3(x-8)/(-8x+67), inverting the denominator.\r<BR>\n" );
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document.write( "3(x-8)/(-8x+67)  ANSWER </SPAN>\n" );
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