document.write( "Question 1016250: If two friends are hiking towards each other on a 17.5 mile hike. One walks 2 2/3 mile an hour and the other 2 1/3 mike n hour. When will they meet? Hour and mile? Who hiked farther? By how much? \n" ); document.write( "
Algebra.Com's Answer #632689 by ankor@dixie-net.com(22740)\"\" \"About 
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If two friends are hiking towards each other on a 17.5 mile hike.
\n" ); document.write( " One walks 2 2/3 mile an hour and the other 2 1/3 mike n hour.
\n" ); document.write( " When will they meet? Hour and mile?
\n" ); document.write( ":
\n" ); document.write( "Let t = time for them to meet
\n" ); document.write( "When they meet, the sum of their distances will be 17.5 mi,
\n" ); document.write( "change their speeds to improper fractions
\n" ); document.write( "Write a distance equation, dist = speed * time
\n" ); document.write( ":
\n" ); document.write( "\"8%2F3\"t + \"7%2F3\"t = 17.5
\n" ); document.write( "multiply by 3 to get rid of those annoying fractions
\n" ); document.write( "8t + 7t = 3(17.5)
\n" ); document.write( "15t = 52.5
\n" ); document.write( "t = 52.5/15
\n" ); document.write( "t = 3.5 hrs for them to meet
\n" ); document.write( "Find the distance each walked, they should add up 17.5
\n" ); document.write( "\"8%2F3\"(3.5) = 9.33 mi
\n" ); document.write( "\"7%2F3\"(3.5) = 8.17 mi
\n" ); document.write( "------------------------
\n" ); document.write( "total distance: 17.5
\n" ); document.write( ":
\n" ); document.write( "\" Who hiked farther? By how much?; I'll let you figure this out
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