document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1016249>Question 1016249</A>: <I><SPAN STYLE=\"word-break: break-all;\"> HELP PLEASE \r<BR>\n" );
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document.write( "A KAYAKER SPENDS 2 HOURS PADDLING UP A STREAM FROM POINT A TO B. QUICKLY TURNS HER KAYAK AROUND AND IMMEDIATLY HEADS BACK DOWN. IT TAKES HER ONLY 1 HOUR TO FLOAT BACK DOWNSTREAM FRON POINT B TO POINT A. IF POINTS A AND B ARE 6 MILES APART WHAT WAS THE KAYAKER'S AVERAGE RATE OF SPEED IN MILES PER HOUR ?\r<BR>\n" );
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document.write( "A 12 MILES PER HOUR<BR>\n" );
document.write( "B 6 MILES PER HOUR <BR>\n" );
document.write( "C 4 MILES PER HOUR <BR>\n" );
document.write( "D 2 MILES PER HOUR </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #632669 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=632669\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  KAYAKER SPENDS 2 HOURS PADDLING UP A STREAM FROM POINT A TO B. QUICKLY TURNS HER KAYAK AROUND AND IMMEDIATELY HEADS BACK DOWN. IT TAKES HER ONLY 1 HOUR TO FLOAT BACK DOWNSTREAM FROM POINT B TO POINT A. IF POINTS A AND B ARE 6 MILES APART WHAT WAS THE KAYAKER'S AVERAGE RATE OF SPEED IN MILES PER HOUR ? \r<BR>\n" );
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document.write( "going from a to b it takes her 2 hours to go 6 miles.\r<BR>\n" );
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document.write( "coming back from b to a it takes her 1 hour to go the same 6 miles.\r<BR>\n" );
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document.write( "the formula you will use a lot in these types of problems is rate * time = distance.\r<BR>\n" );
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document.write( "going upstream rate * time = distance becomes rate * 2 hours = 6 miles.<BR>\n" );
document.write( "solve for rate to get rate = 6/2 = 3 miles per hour.\r<BR>\n" );
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document.write( "go0ing downstream rate * time = distance becomes rate * 1 hour = 6 miles.<BR>\n" );
document.write( "solve for rate to get rate = 6/1 = 6 miles per hour.\r<BR>\n" );
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document.write( "what is here average speed overall?\r<BR>\n" );
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document.write( "the total distance down and up is 2 * 6 = 12 miles.<BR>\n" );
document.write( "the total time down and up is 2 + 1 = 3 hours.\r<BR>\n" );
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document.write( "rate * time = distance becomes rate * 3 = 12<BR>\n" );
document.write( "solve for rate to get rate = 12/3 = 4 miles per hour.\r<BR>\n" );
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document.write( "your solution is that her average speed overall is 4 miles per hour.\r<BR>\n" );
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document.write( "4 miles per hour * 3 hours is equal to 12 miles.<BR>\n" );
document.write( "rate * time = distance\r<BR>\n" );
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document.write( " </SPAN>\n" );
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