document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1016249>Question 1016249</A>: <I><SPAN STYLE=\"word-break: break-all;\"> HELP PLEASE \r<BR>\n" );
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document.write( "A KAYAKER SPENDS 2 HOURS PADDLING UP A STREAM FROM POINT A TO B. QUICKLY TURNS HER KAYAK AROUND AND IMMEDIATLY HEADS BACK DOWN. IT TAKES HER ONLY 1 HOUR TO FLOAT BACK DOWNSTREAM FRON POINT B TO POINT A. IF POINTS A AND B ARE 6 MILES APART WHAT WAS THE KAYAKER'S AVERAGE RATE OF SPEED IN MILES PER HOUR ?\r<BR>\n" );
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document.write( "A 12 MILES PER HOUR<BR>\n" );
document.write( "B 6 MILES PER HOUR <BR>\n" );
document.write( "C 4 MILES PER HOUR <BR>\n" );
document.write( "D 2 MILES PER HOUR </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #632668 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=632668\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Total distance: From A-B + From B-A = 6 mi + 6 mi = 12 mi<BR>\n" );
document.write( "Total time: From A-B + From B-A = 2 hrs + 1 hr = 3 hrs<BR>\n" );
document.write( "Speed = distance/time = 12 mi/3 hr = 4 mi/hr<BR>\n" );
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document.write( "ANSWER : Average speed for the entire trip was 4 mph. (C is correct)\r<BR>\n" );
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