document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1015303>Question 1015303</A>: <I><SPAN STYLE=\"word-break: break-all;\"> after striking the floor a certain ball rebounds 4/5 th of its height from which it has fallen.find total distance that it travel before coming to rest,if it is dropped from a height of 120 m </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #632614 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=632614\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is an infinite sum...actually two sums...the down distances and the up distances...we find those sums by<BR>\n" );
document.write( "S = a / (1-r)<BR>\n" );
document.write( "For the down distances,<BR>\n" );
document.write( "S(downs) = 120 / (1 - 4/5) = 600 m<BR>\n" );
document.write( "For the bounces upward,<BR>\n" );
document.write( "S(ups) = (4/5)(120) / (1 - 4/5) = 480 m<BR>\n" );
document.write( "Total = 1080 m </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );